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Cirdec has given a recursive equation to find the probability of rolling k s-sided dice and getting n specific different results. Here's a more intuitive method to get the same answers (similar to probability tree diagrams [1] [2]): Get at least one result each of 1, 2, and 3 on 4d6 = 1/12 You have one extra die that doesn't need to be one of these ...


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We'll pretend we have k s-sided dice and we are trying to find the probability to get n specific different results. The first die roll we have an n/s chance of getting a number we need and an (s-n)/s chance we get a number we don't need. When we get a number we need we are looking to get n-1 numbers we need on k-1 different dice. When we get a number we ...


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Ah... Probability. In probability, each die is treated independently of the other dice. That is to say, rolling a 1 on one die has no bearing on what the other dice roll. Knowing this, what is the probability of rolling a 1 on a d4? 1/4 or 25%. What is the probability of rolling all 1's? Simply multiply the probabilities, so getting all 1's on 3d4 ...


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The head to head contest of rs conley is wrong: There is an website called anydice.com that do dice probabilities. You can find the "at least" problablilities of 1d20 and 3d6, this means the probabilities of rolling certain number or higher. On a 1d20 the chance of rolling at least 1 is 100% and the chance of rolling 3 on a 3d6 is 100%. An 18 on both ...



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