The description of rapid shot reads:

You can get one extra attack per round with a ranged weapon. The attack is at your highest base attack bonus, but each attack you make in that round (the extra one and the normal ones) takes a -2 penalty. You must use the full attack action (see page 143) to use this feat.

Do you calculate the second attack with your highest base attack -2 as the only modifier or do you also apply your Dexterity bonus to the attack as you would for a regular ranged attack?

For example, if I have a dexterity bonus of +3 and a base attack bonus of +2 am I calculating the attack as +3+2-2=+3 or as +2-2=0?


1 Answer 1


You take your total attack bonus for the attack, that is: any bonuses from weapon enhancements, ability modifiers and other sources, plus your highest base attack bonus.

Normally, every additional attack in a full attack round has its base attack bonus reduced by 5, but keeps all other bonuses.

In the case of Rapid Shot, you gain an additional attack when making a full attack action, but you don't have to reduce your base attack bonus by 5 for this additional attack. Instead, you may make this additional attack as if it was your first and most powerful attack.

If your base attack bonus (BAB) is +6, you can make a full attack action consisting of 2 attacks. The first attack is made with +6 BAB and the second with +1 BAB:

  1. +6 BAB +3 Dex = +9 Attack Bonus
  2. +1 BAB +3 Dex = +4 Attack Bonus

With Rapid Shot(RS) and its -2 Attack Bonus:

  1. +6 BAB +3 Dex -2 RS = +7 Attack Bonus (Rapid Shot's additional attack)
  2. +6 BAB +3 Dex -2 RS = +7 Attack Bonus
  3. +1 BAB +3 Dex -2 RS = +2 Attack Bonus

Keep in mind that you must always perform your attacks in order of highest base attack bonus to lowest.


You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .