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The description of rapid shot reads:

You can get one extra attack per round with a ranged weapon. The attack is at your highest base attack bonus, but each attack you make in that round (the extra one and the normal ones) takes a -2 penalty. You must use the full attack action (see page 143) to use this feat.

Do you calculate the second attack with your highest base attack -2 as the only modifier or do you also apply your Dexterity bonus to the attack as you would for a regular ranged attack?

For example, if I have a dexterity bonus of +3 and a base attack bonus of +2 am I calculating the attack as +3+2-2=+3 or as +2-2=0?

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You take your total attack bonus for the attack, that is: any bonuses from weapon enhancements, ability modifiers and other sources, plus your highest base attack bonus.

Normally, every additional attack in a full attack round has its base attack bonus reduced by 5, but keeps all other bonuses.

In the case of Rapid Shot, you gain an additional attack when making a full attack action, but you don't have to reduce your base attack bonus by 5 for this additional attack. Instead, you may make this additional attack as if it was your first and most powerful attack.

If your base attack bonus (BAB) is +6, you can make a full attack action consisting of 2 attacks. The first attack is made with +6 BAB and the second with +1 BAB:

  1. +6 BAB +3 Dex = +9 Attack Bonus
  2. +1 BAB +3 Dex = +4 Attack Bonus

With Rapid Shot(RS) and its -2 Attack Bonus:

  1. +6 BAB +3 Dex -2 RS = +7 Attack Bonus (Rapid Shot's additional attack)
  2. +6 BAB +3 Dex -2 RS = +7 Attack Bonus
  3. +1 BAB +3 Dex -2 RS = +2 Attack Bonus

Keep in mind that you must always perform your attacks in order of highest base attack bonus to lowest.

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