I'm playing D&D 5e as a DM for about a 3-4 sessions now and the math involved in the Wizard's ability Arcane Ward is a little unclear to me. All of my players just reached level 2 and one of the players is a Wizard who chose The School of Abjuration archetype and he now has the Arcane Ward ability.
Playing by the PHB(p.109) the ability states:
Starting at 2nd level, you can weave magic around yourself for protection. When you cast an abjuration spell of 1st level or higher, you can simultaneously use a strand of the spell's magic to create a magical ward on yourself that lasts until you finish a long rest. The ward has hit points equal to twice your wizard level + your Intelligence modifier.
With his Intelligence modifier (+3) and Wizard level 2 the equation should be:
$$ \begin{align} {Temporary\;HP} &= ( 2 \times {Wizard\;level} ) + {Int\;modifier} \\ &= ( 2 \times 2 ) + 3 \\ &= 4 + 3 \\ &= 7 \end{align} $$
But it can also be:
$$ \begin{align} {Temporary\;HP} &= 2 \times ( {Wizard\;level} + {Int\;modifier} ) \\ &= 2 \times ( 2 + 3 ) \\ &= 2 \times 5 \\ &= 10 \end{align} $$
The text makes it unclear.