Let's assume a player has very bad luck (as in, most attack rolls result in failures, with a bad record of 1s' showing up at the worst moments).

What are the classes that are the least reliant on the player's dice rolls for binary (succeed or fail) effects?

Note: One example would be the fireball-hurling wizard: While the player would need to launch d6 damage, and the targets need to roll a saving throw, the fireball itself always succeeds, and the damage is always a lot of dices, minimizing the impact of a 1.


closed as too broad by DuckTapeAl, Thomas Jacobs, Szega, Mołot, KorvinStarmast Mar 24 at 12:31

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 2
    \$\begingroup\$ Do you mean any dice rolls, or this player's rolls only? \$\endgroup\$ – enkryptor Mar 24 at 11:01
  • \$\begingroup\$ It seems we have a friend in common. Is he Brazilian? \$\endgroup\$ – ShadowKras Mar 24 at 12:37
  • 4
    \$\begingroup\$ As a player with impossibly bad luck, this is often my goal. (My alternative goal is to overwhelm the luck gods with my rolls, ensuring that at least one will be successful.) Narrowing this could work, to something like How can a mundane warrior roll the least amount of dice and still defeat his foes? or What arcane caster needs to make the fewest number of player-facing rolls to contribute meaningfully? but I doubt it. Instead, I think you might be better off overall first developing a build then asking how to optimize it so as to reduce die rolls on the player's part. \$\endgroup\$ – Hey I Can Chan Mar 24 at 14:09
  • \$\begingroup\$ @enkryptor: Player attack rolls, mostly. \$\endgroup\$ – paercebal Mar 25 at 16:14
  • \$\begingroup\$ @ShadowKras: He's French. That's me actually. T_T \$\endgroup\$ – paercebal Mar 25 at 16:14

Browse other questions tagged or ask your own question.