The fancy unconscious/initial dig is not that important. Arguably the PC was awake after being dropped 5' into a pit, but prone, as being pushed 5' by wind then dropped 5' is a lot more impactful than a slap, and definitely shakes the creature.
So the question becomes, there is a creature prone in a 5' square pit. Someone uses mold earth to bury them. How quickly do they die?
The answer is:
Mold Earth doesn't work that way
Mold Earth cannot be used to do damage. You aren't allowed to grapple someone with mold earth, restrain them with mold earth, or push them around with mold earth. You can make earth flow along the ground, you cannot make it flow over someone.
If you target an area of loose earth, you can instantaneously excavate it, move it along the ground, and deposit it up to 5 feet away. This movement doesn’t have enough force to cause damage.
So the earth fills the hole, and the PC ends up on the surface again, if you allow using Mold Earth to lift someone; or the dirt doesn't end up over the PC. Because the earth you move can only move along the ground, it cannot end up above the PC in the hole. Because in order to be above the PC, it was not moving along the ground.
Now, you could read "along the ground" as "so long as any part of it is touching the ground", but then Mold Earth becomes a way to drop tonnes of matter as an action; this contrived example is just a hard way to do it.
There is a type of rules bending where you do a bunch of contrived things chained together, as if the complexity of the chain makes the result somehow more justified. This just looks like an example of it.
Mold Earth is a powerful utility cantrip, it is not a combat cantrip for killing creatures directly.
But lets assume you are ok with Mold Earth being used as a weapon.
It is my game, Mold Earth works like that
A 5' deep hole with vertical sides is not stable in loose Earth. The angle of loose Earth is about 30' off horizontal (give or take), after which it collapses, and of the Earth wasn't loose Mold Earth cannot have moved it.
As the pit can be no more than 5' wide, that means the bottom is no more than 2.5' down. You then put a 5' cube of Earth above them; this collapses into a cone immediately.
$$(5 feet)^3=2 \pi r^2 \frac{h}{3} - 4 ft^3 $$
The 2 here represents the double cone (from the depression and the pile above it), and the \$ - 4 ft^3\$ term the rough volume of the buried person.
With a 30 degree angle, \$h = \frac{r}{2}\$, so we get
$$(5 feet)^3=h^3 \frac{8 \pi}{3} - 4 ft^3 $$
$$ \frac{363}{8 \pi} feet^3 =h^3$$
$$ h = 2.4 feet $$
Or about 2.4 + 2.4 feet deep.
From NASA male american chests are about 25 cm deep, or about 10 inches. So the total depth the person is buried is about 4 feet in the center.
The person is about 55 cm broad (call it 2 feet) and 160 cm tall (call it 6 feet). Every 2 feet away from center the dirt is 2 feet shorter, as both the top and bottom slope together; assuming centered, the head and feet are about 1 foot down, and the arms are under 1-2 feet of dirt.
1 cubic foot of dirt weighs about 80 lbs. if not crushed to death, they can probably kick their legs free (legs are strong).
Getting even a bit of vibration in your extremities would start making the dirt above shift, giving you more freedom to move. Your lungs wouldn't be emptied by that pressure, just compressed. So you will have some time to attempt to escape.
Someone outside who knows where your face is should have no problem digging off the foot of dirt before you suffocate.
Are you crushed to death?
While the weight of dirt is large, they are in effect a fluid-filled tunnel in it. Some of the force of the dirt will go around the body, and the body will be supported from below and from the sides by more dirt.
If you are 8 feet deep in a pool, you have more mass over you than you would with this dirt pile on top of you, and that mass has less structure than the dirt does. You aren't going to insta-gib just from the weight.