How can I get "Number of dice in pool A higher than highest of pool B" in anydice?

Question

What I'm looking for is this: pools A and B roll Xd6 and Yd6, respectively. The result is determined as follows:

1. The highest roll among all dice is r_h, and the pool it comes from is P_h.

2. The other pool is P_t, and the highest roll from that pool is r_t.

3. The magnitude of the result, R, is equal to the number of rolls in P_h that are higher than r_t.

4. If P_h is A, the result is +R. If P_h is B, the result is -R. (If r_h = r_t, the result is a tie.)

Example:

[6 6 5] vs [1 2] -> winner is A, with R = +3
[4 4 3] vs [6 6] -> winner is B, with R = -2
[4 4] vs [4 4 2] -> tie, R = 0

Answer 1

If I'm reading your question correctly (which is not guaranteed: I've read through it a half-dozen times, and I'm still not 100% sure I've got it, but maybe that's what afternoon naps on snowy days do...), then the solution-function is almost the same as Ilmari's answer from the linked post. The only change is what to do in case of a tie. (Nothing special!)

function: A:s vs B:s {
  result: (A > 1@B) - (B > 1@A)
}

Recall that a group of dice stored as a sequence (A:s) automatically sorts high-to-low and elements are @-accessed, so 1@A outputs the first (i.e. highest) roll of group A. The comparison operator acting on a sequence vs. a number will generate a truth-count as its output, so A>1@B produces "the number of rolls in A greater than the highest of B". And in the case of a tie, we know (by construction) that A>1@B and B>1@A will both be zero, so we get the result you want =)

Function defined, if you want to see it in action a simple call like

output [6d6 vs 4d6] named "6 vs 4"

or

loop X over {3..6} {
  output [Xd6 vs 4d6] named "[X]d6 vs 4d6" 
}

will do the trick. It's pretty time-intensive, though, so you may end up running lots of "combats" individually.

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_{I will be donating all rep from this answer to a post of Ilmari's choice or, absent such a choice, to a post of Ilmari's that I choose (via bounty). Because this code is basically just theirs, with one tweak to fit your tie-condition.}