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I'm working on a custom ttrpg system and I've noticed a lot of answers to questions in here regarding AnyDice. You would roll two die (such as a d6 and a d8) against a third die of any size up to a d12. The third die determines difficulty. Having at least 1 die meet or exceed the difficulty is a minor success, while both meeting or exceeding is a major success. Any help on how to set this up would be appreciated.

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    – Someone_Evil
    Jul 19, 2023 at 8:04

1 Answer 1

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The main trick you need here is to make two comparisons to a single row. The way to do this is to cast it to a function. Then we just get to treat our variables as an outcome of a roll, not dice.

We then just compare the result each of the two dice with the result of the target die. Resulting the sum means 1 means a minor success and 2 a major.

function: roll A:n B:n against T:n {
  result: (A>=T)+(B>=T)
}

output [roll 1d8 1d6 against d12]
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  • \$\begingroup\$ It might be worth noting that the A:n B:n part of the definition causes each of the first two rolls to be summed into a single number even if there's more than one die in each rolled pool. If you defined the function using A:s B:s, the rolls would be converted into sequences instead, which would let you do e.g. [roll 2d8 3d6 against d12] and get a count ranging from zero to 2 + 3 = 5 of all the dice in 2d8 and 3d6 meeting or exceeding the random d12 target. \$\endgroup\$ Jul 19, 2023 at 21:42

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