I want to better understand impact on probability of success granted by stat increases with the following dice mechanism:
$$ \text{Dice Test} = \text{Roll}\ [3 + \text{STAT}]\text{d}6 : \text{Keep Highest 3} $$
- Result compared to difficulty number, success if equal or higher.
- STAT ranks from 0-5.
- AnyDice data.
At STAT 0, difficulty 11 represents a 50/50 chance of success. How much more likely is success at STAT 1-5 and difficulty 11?
Also, how is the probability of success altered by increasing/decreasing the difficulty at every STAT level? Say difficulty 5, 7, 9, 11, 13, 15, and 17 at every level of STAT 0-5.
I imagine the second question is significantly more calculation intensive than the first. I am unsure how to determine these numbers myself. If someone wanted to simply explain how the changes to probability of success could be computed for the aforementioned formulae, and not do the computation themselves, I would be much obliged.
Say difficulty 5, 7, 9, 11, 13, 15, 17, and 19 at STAT 0-5
, that's 8 different difficulties and 6 possible stat values, is this correct? What stat value goes with what difficulty? (Also, if it's always "keep highest 3", 19 is not really achievable.) \$\endgroup\$