The damage for the spell delayed blast fireball is listed as:

The spell’s base damage is 12d6. If at the end of your turn the bead has not yet detonated, the damage increases by 1d6.

The spell's duration is "Concentration, up to 1 minute".

Does this damage increase repeat on each of your turns throughout the spell's duration?
Or does it only apply to the turn when you cast the spell?

I tried to draw comparison to the 3.5e version of the spell, but according to the d20 SRD, there is no damage bonus for delaying the blast in D&D 3.5e; the spell is simply more powerful than fireball.


Yes, every turn you delay the explosion you increase the damage by +1d6, up to the max of 10 turns, 12d6+10d6 = 22d6.

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  • \$\begingroup\$ Is the max duration due to the fact that a round is 6 seconds (1 min concentration) or is that RAW for the spell? \$\endgroup\$ – Premier Bromanov Jul 15 '15 at 21:28
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    \$\begingroup\$ 1 round = 6 seconds, 60 seconds in 1 min, so 60/6 = 10 rounds. So, Yes, due to both 1 round = 6 seconds and RAW 1 min duration. \$\endgroup\$ – GreySage Jul 15 '15 at 21:31
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    \$\begingroup\$ And if you cast the spell with a level 9 slot, the damage can go up to 24d6! \$\endgroup\$ – Alexis Wilke Mar 19 '16 at 8:15

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