This question is a follow up of This Question concerning casting Warding Bond on multiple allies. It was found that This Tweet confirmed my suspicions that it is possible, given a separate pair of rings for each separate creature I want to effect when I cast Warding Bond, to share damage with multiple allies.

Now that we know this is possible, I am curious as to the nature of the survivability of my level 5 Hill Dwarf War Cleric using the Tough feat and taking the average HP every level up for a current total of 53 HP.

My party consists currently of myself (War Cleric), a Life Cleric (also a Hill Dwarf), a Rogue, 2 weapon Fighter, and a Warlock. Next session we will be joined by a Wizard. We are at a static level 5.

The rogue is wearing the matching ring of my first pair of Platinum Rings that are required to cast the spell.

It is safe to assume the more simultaneous bonds I have active at any given moment, the lower my survival rate becomes. Sharing 1/2 damage from multiple sources is bound to be hazardous since there is no way to reduce that damage even farther.

How thin can I spread myself without being suicidal?

  • \$\begingroup\$ is multiclassing an option? \$\endgroup\$
    – András
    Commented Dec 13, 2016 at 14:34
  • \$\begingroup\$ I'm not sure this can be transformed into an answerable question. There are too many variables, primarily the AC of your allies (how often they take damage), and the nature of your opponents (any Area of Effect spells are going to be brutal to you, for instance). \$\endgroup\$ Commented Dec 13, 2016 at 15:20
  • \$\begingroup\$ @keithcurtis hmm...that's what I was afraid of.... Still; I'm going to risk leaving this open until voted to be closed or a compromise can be reached. I have come to value the answers of everyone here. \$\endgroup\$
    – Airatome
    Commented Dec 13, 2016 at 15:23
  • \$\begingroup\$ Are you looking for a mathematically derived answer? One can be provided regarding the relative benefits and costs of your described approach, but it will not contain specifics because of the lack of information about the allies and foes in the engagement. \$\endgroup\$
    – tillmas
    Commented Dec 13, 2016 at 15:25
  • 1
    \$\begingroup\$ @Airatome, your question is right at the edge of a first order answer (powerpoint engineering). It is getting at complicated relationships that drive answers away from statistical responses (because you only care about a single engagement and not the average of many, many engagements). I would be happy to help you answer the specifics using numerical methods (its what I do for a living, and this kind of application to hobby wargaming interests me very much). \$\endgroup\$
    – tillmas
    Commented Dec 13, 2016 at 16:05

3 Answers 3


Warding Bond ends if it is cast on either creature a second time.

All of this would be math is pointless.

Read. Your. Spells. People.

Warding bond says:

The spell ends if you drop to 0 hit points or if you and the target become separated by more than 60 feet. It also ends if the spell is cast again on either of the connected creatures.

If you have cast Warding Bond and someone cast Warding Bond on either you or the target of your casting, then the casting of Warding Bond by you is ended.

  • \$\begingroup\$ Ive made some edits for formatting and readability, let me know if they look okay. \$\endgroup\$ Commented Jan 20, 2021 at 21:57
  • \$\begingroup\$ Interesting and relevant, this question is also active right now. rpg.stackexchange.com/questions/78909/… \$\endgroup\$ Commented Jan 21, 2021 at 4:24
  • \$\begingroup\$ @Thomas Markov Looks good to me. \$\endgroup\$ Commented Feb 2, 2021 at 14:22
  • \$\begingroup\$ Crawford has confirmed the opposite. twitter.com/jeremyecrawford/status/727306599576952832?lang=en The spell is only cast 'on' the other creature (the target). The spell would end if someone else (a second cleric for example) cast Warding bond on the caster. This wording with 'again' is confusing, but from crawford's tweet it seems this line was meant to prevent two clerics from casting warding bond on each other. \$\endgroup\$ Commented Nov 15, 2022 at 1:18

I will attempt to clarify the potential value of this by using average combat mechanics, and then see where the multiple warding bonds will provide value.

Overall, your party and the enemy will do average damage of:

(Probability of Hit) x (Average Damage) x (number of rounds)

Note that the Probability of Hit is related to (target AC - Attack Bonus), and is 50% when (target AC - Attack Bonus) = 10.5

The winner of an attrition based conflict (see Lanchester Model of Attrition Warfare) will be the side that can inflict average damage until the enemy is dead, and then have some residual strength of their own. In D&D parlance, that means that:

(Allies HP) / (Enemy Rate of Damage) > (Enemies HP) / (Allies Rate of Damage)

From this, your Warding Bond will not affect your Allies Rate of Damage, or your Enemies HP, so you are working entirely on the left hand side of the inequality. In order to be successful, your dwarf must survive enough damage to provide your allies resistance so that you get a two fold bonus to the inequality (since Enemy Rate of Damage is reduced by 1/2).

In addition, the AC bonus that you provide to those affected with the spell gives them an additional 5% reduction in the enemies probability of damaging them per round. This will further serve to reduce the damage taken on the left hand side of the equation.

The answer to your question lies in comparing all of the parameters that I have listed. I will facilitate this by providing four bounding conditions:

  1. The enemy has vastly more HP than your dwarf, relative to the average rate of damage, and they do damage at a higher rate than your allies. This is the suicidal case you reference.

  2. The enemy has far more HP than your dwarf, but they do damage at a much lower rate.

  3. The enemy has far fewer HP than your dwarf, but they do damage at a much higher rate.

  4. The enemy has far fewer HP than your dwarf and they do damage at a much lower rate.

In case 1, it is unlikely (5%) that you will see the benefit of the spell, and your dwarf is very much at risk. In case 4, it is also unlikely that you will see the benefit of the spell, largely because your allied force didn't need it.

In cases 2 and 3, the benefit of the spell can swing the tide. There isn't a clear cut use case, since it will depend on the specific engagement. In these cases, if the enemies average damage is more than double your force's average damage, then the spell is a bad idea (so is combat).

In this case, we now switch back to the first formula.

(number of rounds for attrition) = (Enemy HP) / (Probability of Hit * Average Damage)

using a Ph of 50%, the dwarf will survive (most of the time) when:

(Enemy HP) / (0.5 * Friendly Avg Damage) < (Dwarf HP) / (0.45 * 0.5 * Enemy Avg Damage)

(Note that the 0.45 is for the AC change, and the 0.5 is the resistance).

This tells us that the probability is that the dwarf will survive ~50% of the time when you have ~1/2 as many hit points as the opposing force. If you have more HP than that, you will survive more. If you roll better (or the enemy rolls worse) you will survive more.

From this, you could consider spreading yourself "that" thin. Pick the hardest hitting allies who are the weakest, and start bonding them until you get to a number (understanding that the enemies rate of damage to the dwarf will go up linearly with each ally you bond) that is close to the ratio of your HP to the entire enemy force's HP.


  1. The dwarf is not fighting. If the dwarf is ALSO taking direct damage, it complicates the equations a bit (makes them second order), and I would need a lot more detail to solve them (including the specific parameters of the engagement on both sides).

  2. There are no area based spells being cast against the multiple bonded allies

  3. No consideration was taken for the enhancement in saving throws for bonded allies (requires much more specific model).

  • \$\begingroup\$ "since Enemy Rate of Damage is reduced by 1/2". I don't think you understand how Warding Bond works. You give resistance to an ally (they take half damage), but you take the same amount of damage they do (you take half damage as well). There is no net effect on party HP. The advantage of this spell is the +1 AC (your target is 5% less likely to get hit), and you are able to keep squishier PCs alive. There is no net change to the party HP, only the ability to re-distribute where damage is applied. \$\endgroup\$
    – Shem
    Commented Dec 30, 2016 at 19:49
  • \$\begingroup\$ I do understand it, and that is baked into the calculus. Note my first assumption listed. You are only able to reduce by half the rate of damage if the caster is also NOT taking direct damage. If he is also taking direct damage then the only benefit is the +1 to AC which translates into a bit less than a 5% gain. \$\endgroup\$
    – tillmas
    Commented Dec 30, 2016 at 19:51
  • \$\begingroup\$ Example: Cleric casts "Warding Bond" on Rogue. A dragon strikes warded Rogue for 50 damage. Rogue takes 25 damage (half of incoming 50). Cleric immediately also takes 25 damage (same as rogue). Net damage to the party: 50. There is no overall damage reduction. \$\endgroup\$
    – Shem
    Commented Dec 30, 2016 at 19:57
  • \$\begingroup\$ @Shem please READ my answer. I directly address your statements in the assumptions. My answer is based on the cleric being a damage sponge to keep people alive, and the conditions where that has value. \$\endgroup\$
    – tillmas
    Commented Dec 30, 2016 at 21:07

You can survive this

You can increase survivability drastically through this loophole. However, it requires everyone else to be level 2 clerics (or, at the very least, have some magic items).

Key Note: If you are cast warding bond upon, you may still cast warding bond yourself without ending the spell. This is because you are not the target of your own spell. This allows you to build a chain of characters linked by this spell.

The steps:

  1. Cast warding bond onto a second cleric (cleric \$2\$). This counts as the spell being cast on that cleric only.
  2. Have cleric \$2\$ cast the same spell on a third cleric (cleric \$3\$). Since this spell targets someone other than the caster, then the spell does not break. You now have a chain of 3 clerics.
  3. Repeat until cleric \$N\$, where \$N\$ is the total number of clerics in the party.

The damage calculation:

  1. If cleric \$N\$ takes \$M\$ damage, then that damage is split in half due to resistance, so \$M/2\$.
  2. Cleric \$N-1\$ takes \$M/2\$ damage. However, since warding bond is also active on this one, they have resistance to that damage. So, they take \$M/4\$.
  3. Cleric \$N-2\$ takes \$M/8\$ damage for the same logic as step 2.
  4. In general, Cleric \$N-a\$ will take damage equal to $$M\over 2^{a+1}$$

The effect of this, overall, is that someone taking 100 points of damage will be able to split that 100 HP to everyone in the party with change (if everyone was a cleric). This is better than just splitting it 50/50 between two characters.

As with all chains, of course, there are weak links that you must cover up:

Weaknesses of strategy:

  1. The cleric being hit will always take \$M/2\$ damage, even if they are not the last person in the chain. That is, if you hit the chain in the middle, the damage only propagates downward, not upward, along the series.
  2. The first cleric who cast the spell does not have resistance to anything. As such, it would be smart to have the Barbarian/Cleric multiclass be the first cleric of this chain.
  3. Concentration is difficult to maintain for spellcasters since anyone getting hit means a concentration save for everyone maintaining concentration spells.

Fun Quirks:

  1. Your party is resistant to AoE attacks. If everyone (all \$N\$ clerics) gets hit with AoE damage, it will trickle down for everyone. If the AoE was supposed to deal \$M\$ damage and everyone failed their saves, then any given cleric will take:

    N: \$M/2\$ = \$M/2\$

    N-1: \$M/2 + (M/2)/2\$ = \$3M/4\$

    N-2: \$M/2 + (M/2 + (M/2)/2)/2\$ = \$7M/8\$

    N-3: \$M/2 + (M/2 + (M/2 + (M/2)/2)/2)/2\$ = \$15M/16\$

    N-a, where \$a\$ is distance from last person in the chain, starting at 0 and ending at \$N-1\$: $$M * {2^{a+1}-1\over 2^{a+1}}$$

    This means, the maximum damage you can take is \$M\$ if and only if everyone of your party fails their save. If someone succeeds on their save, that reduces the damage you will take, assuming you're down the chain (which, as a squishy, you should be).

  2. An enemy cleric cannot break the chain by casting warding bond on a member of this chain, since it requires a "willing target". This safeguards you from a savvy enemy cleric who tries to break the entire chain at once (but you are still vulnerable to their Dispel Magic).

Shoring up the weaknesses:

  1. Do not have the squishies be part of the chain. You, as the main cleric, focus on healing and other support spells. Allow the Barbarian, Rogue, and Paladin to arrange themselves in a warding bond chain. This way, anyone who takes damage as a result of being in this chain, would be able to withstand the full damage they would have taken anyway.
  2. Put the Barbarian as the first caster of warding bond (cleric \$1\$), and have them be the face of the chain. They would receive all damage as they normally would -- that is, halved -- and the rest of the damage will be "lost" since there is nobody else down the chain to propagate it to.
  3. Then, cleric \$2\$ must be the squishiest member of the chain. This ensures they will receive half damage if they are attacked directly, and throw the other half over to the tanky Barbarian, and they will also receive the least damage from a non-AoE spell if anyone further up the chain takes damage.
  4. So, arrange the chain in this manner: ["Tankiest"]->["Squishiest"]->[2nd "squishiest"]->[2nd "tankiest"]
  5. You may also use temp HP as any damage you receive from warding bond will have to go through the temp HP first.

I'll ignore the smell of cheese on this one, as this is a fun option to think about.

But what if you weren't all clerics?

If you can find rings of spell storing for each member of the party, you can store warding bond in each ring twice and (possibly) a healing word, so you can do the process noted above.

But in the absence of all of that, I'd advise you to apply this spell only to those that can take a quarter of the damage after resistance (such as the Rogue), to not apply it to party members who have it anyway (such as the Barbarian), and to have a lot of healing potions and healing scrolls at the ready!

Under this system, you only need to cast warding bond once.

  • 2
    \$\begingroup\$ This is a delightful serving of Ementhal complete with wine, grapes, and a fresh baguette. +1. \$\endgroup\$ Commented Dec 14, 2016 at 13:44
  • 1
    \$\begingroup\$ When you cast the spell, you cast it on yourself and someone else. Casting WB while already under the influence of WB breaks the first one. \$\endgroup\$
    – Shem
    Commented Dec 30, 2016 at 20:01
  • \$\begingroup\$ @Shem No. Refer to Crawford's tweet linked in the OP, which is the entire basis of this answer. \$\endgroup\$
    – user27327
    Commented Jan 13, 2017 at 9:01
  • \$\begingroup\$ The effects of rounding down add up pretty well, right? e.g. 27 damage -> 13 + 6 + 3 + 1 + 0 + 0 + ... = 23 damage. In general you won't reduce more than log2 (31->26, 32->32), but many numbers are small. \$\endgroup\$
    – Cireo
    Commented Jul 3, 2019 at 23:07

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