Does a fireball ignore total cover?

Question

Related: What exact dimensions does a physical cone AoE template need to have?

From PHB, p.204;

A spell’s effect expands in straight lines from the point of origin. If no unblocked straight line extends from the point of origin to a location within the area of effect, that location isn’t included in the spell’s area. To block one of these imaginary lines, an obstruction must provide total cover

However, from the text of the fireball spell,

The fire spreads around corners.

In the case of someone hiding around a corner, I would personally rule that they have total cover. Does this mean that the flame from a fireball will ignore total cover? Or does it only apply to one specific condition under which a creature can have total cover from another (for instance, if the creature was inside of a welded steel box)?

Answer 1

RAW Fireball appears to ignore full cover, if there is a path fully within range of the effect that can reach the target, as this spell specifically travels around corners.

If there are no corners this spell can successively travel around within it's effect radius to reach the target, then the target cannot be reached by the effect, and has total cover, causing it to ignore the effect entirely.

Note, there is no limit specified by the spell, stating how many corners can be traveled around, or how arbitrarily complex the path it must follow can be. This leads me to conclude, if you can draw a line that remains entirely within the effect radius that reaches the target, they are hit by the spell.

Also, another thing to note, this is not a point originated explosion as in normal physics, but rather a magical effect that fills any area it can reach with magical flames.

Answer 2

Yes if it can get to you.

Dunno if anyone posted this already but a Fireball is a 20 foot radius sphere according to PHb pg241.

A sphere with a 20 foot radius has:

A volume of 33510.3 cubic feet, an area of 5026.55 square feet And a circumference of 125.664 feet

The volume was what's important in old editions, but not 5e. In a typical 10 foot wide, 10 foot high dungeon corridor, 33510.3 cubic feet exploded roughly 160 feet in each direction from its point of origin.

So since the range is only 150 feet the caster would be caught in the blast in older editions.

Now just to complicate things a little, the definition of a sphere is "a set of points in three dimensional space that are located at and equal distance r (the radius) from a given point (the center point).

Does that mean the Fireball is hollow and only burns around the surface of the sphere? If so, does it maintain its 20 foot radius into the corridor and burning the ground or into other rooms around it rather than using the tunnel like the barrel of a cannon?

Since RAW 5e say it "blossoms with a low roar into an explosion of flame" and "spreads around corners" I interpret that to mean it doesn't just appear as a hollow sphere of fire, but grows into one. I still give that a maximum of 20 foot radius and don't have it expand mathematically to full 33510.3 volume capacity because the spell specifically states 20 foot radius and not 33510.3 volume.

If you are within a 20 foot radius of the point of origin, regardless of how many corners there are, and water could get to you, then the fireball will get you. If you were sealed in cement, then no it won't.