11
\$\begingroup\$

I've been looking at the possible constructs in current Pathfinder bestiaries looking for options for a crafter character and I couldn't help but notice that the pricing of the clockwork soldier (Bestiary 3) seems unreasonable.

It's a CR6 construct, but the price is 37,000gp. Even following the pricing guidelines offered in Ultimate Magic I can't understand the price. Can anyone explain why this construct is so expensive for its abilities?

\$\endgroup\$
0

2 Answers 2

10
\$\begingroup\$

The rules for construct price say:

As a rough guideline, a construct’s price is equal to its challenge rating squared, then multiplied by 500 gp. Constructs with a fractional CR rating base their price on that fraction of 500 gp.

And:

The first special ability is included in the construct’s base cost. The next two special abilities increase the calculated price by +1/2 CR per ability. Thereafter, any additional special abilities add +1 CR per ability.

The Clockwork Soldier has four special abilities: efficient winding, proficient, standby, and latch. This gives it a CR boost of 2 for the purposes of cost. In addition, it has a Strength of 28, which is higher than most other CR 6 monsters, which can count as a special ability for the construct price rules. This gives us a total of CR 9 for pricing. CR 9 constructs cost 40500 gp, according to the formula. 40500 is a bit higher than the listed 37000 listed, but it might be adjusted down due to other factors.

Alternately, not counting the high Strength, a CR 8 construct costs 32000 gp, according to the construct price rules. This is a few thousand lower that the 37000 listed, but it's decently close.

\$\endgroup\$
1
\$\begingroup\$

Working Backwards you find they ruled it as a CR 7 monster - because you missed one thing clockworks are 150% of cost of a construct so with a CR 7 monster squared * 500 * 1.5 is 36750 round up to 37000.

\$\endgroup\$
1
  • \$\begingroup\$ This should be a comment on DuckTapeAl's answer. Unfortunately, you don't have enough reputation to make comments, so... Maybe put the mathematics of DuckTapeAl into this answer, to make it complete? \$\endgroup\$
    – GMJoe
    Commented Sep 1, 2014 at 3:29

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .