I've looked on several resources and I can't get to the bottom of whether an Artificer recharges spell slots on short/long rest?

Lots of articles refer to the class as a "short rest caster" or "warlock-like" but I haven't been able to find anything in the handbooks which make it very clear (to me at least).

Some places seem to say short rest:

This wondrous creation is capable of regenerating its power over a short rest period (1 hour), which allows artificers to regenerate their spell slots much like a warlock can. https://gadriel.fandom.com/wiki/Artificer_(DND_5th_edition)

While others say long rest:

You regain all expended spell slots when you finish a long rest.

It seems to make a huge difference to the power of an artificer, particularly as they gain spell slots very slowly. Is there anything solid to back up the "regain on a short rest" that gets talked about so much?


1 Answer 1


The first link you provided is a homebrew (non-official) class named artificer.

The official artificer (published in Tasha's Cauldron of Everything and Eberron: Rising from the Last War) regains their spell slots after a long rest:

To cast one of your artificer spells of 1st level or higher, you must expend a slot of the spell’s level or higher. You regain all expended spell slots when you finish a long rest.

-E:RftLW pp. 55-56, TCoE pg. 11

  • \$\begingroup\$ I removed the reference to Wayfinder’s Guide since it is technically playtest content, not official content. \$\endgroup\$ Dec 8, 2021 at 2:03
  • \$\begingroup\$ Thanks for clarifying, that makes a lot of sense! I've also seen that Artificers get Arcane Recovery at L5, which does help them recover slots on a short rest, but I can't find much more detail on that? Is that part of the official class too? \$\endgroup\$
    – David258
    Dec 8, 2021 at 9:57
  • 1
    \$\begingroup\$ @David258 No it is not. If you want to play an artificer, I recommend purchasing Tasha's Cauldron of Everything, it contains lots of extra options in addition to the artificer. \$\endgroup\$ Dec 8, 2021 at 13:26

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .